openURL second parameter optional?

**mattekure** · May 3rd, 2022, 19:50

In the new openURL function, the documentation indicates that the second parameter for the callback function is optional. But if I try it without a callback function defined, I get an error of invalid parameter 2.

**Moon Wizard** · May 3rd, 2022, 20:01

Can you try "nil" instead?

JPG

**mattekure** · May 3rd, 2022, 20:03

Originally Posted by Moon Wizard

Can you try "nil" instead?

JPG

Yeah, that works.

So Interface.openURL("https://someurl.com", nil) works

I tried these which did not work
Interface.openURL("https://someurl.com")
Interface.openURL("https://someurl.com", "")

thanks

**Moon Wizard** · May 3rd, 2022, 20:06

I'll look at updating the code to check for the parameter existence first, but you can use nil for now.

Regards,
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**Moon Wizard** · May 6th, 2022, 19:09

Fixed in beta release today.

Cheers,
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**travin** · March 26th, 2023, 19:10

Sorry to necro this thread, but when processing the callback, all I get is the URL and not the generated response. Did I miss something or is the generated response stored somewhere else?

**Moon Wizard** · March 26th, 2023, 23:42

The callback will receive two parameters (sURL, sResponse).

Regards,
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**travin** · March 27th, 2023, 00:34

Originally Posted by Moon Wizard

The callback will receive two parameters (sURL, sResponse).

Regards,
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Thank you!

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